JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Analyzing +4 | -1

The dimensions of

{e^2}/4\mathrm{\pi }{\mathrm{\varepsilon }_0}hc,

, where

e,\;{\mathrm{\varepsilon }_0},\mathrm{\;}h\;\mathrm{and\;}c

are electronic charge, electric permittivity, Planck’s constant and velocity of light in vacuum respectively, are

View answer and explanation

Correct option: A

\left[ {{\mathrm{M}^0}{\mathrm{L}^0}{\mathrm{T}^0}} \right]

Option A is correct because the expression is dimensionless, representing the fine-structure constant.

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