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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
Suppose that the graph of y=f(x)y=f(x), contains the points (0,4)(0,4) and (2,7)(2,7). If f′f^{\prime} is continuous then ∫02f′(x)dx\int\limits_{0}^2 f^{\prime}(x) d x is equal to
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Correct option: C
3
Option C (3) is correct because the integral of f′(x)f'(x) from 0 to 2 is simply f(2)−f(0)f(2) - f(0), which is given as 7 - 4 = 3.

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