JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1

3\,\,\cos \,x \ne 2\,\,\sin x

, then the general solution of

{\sin ^2}x - \cos \,\,2x = 2 - \sin \,\,2x

View answer and explanation

Correct option: C

\left( {4n \pm 1} \right)\frac{\pi }{2},\,\;n \in Z

Option C (

\left( {4n \pm 1} \right)\frac{\pi }{{2}},\\;\,n \in Z

) is correct because solving the trigonometric equation leads to this general solution.

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