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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Analyzing +4 | -1
If sin⁡2θ−2sin⁡θ−1=0\sin ^2 \theta-2 \sin \theta-1=0 is to be satisfied for exactly 4 distinct values of θ∈[0,nπ],n∈N\theta \in[0, n \pi], n \in N, then the least value of nn is
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Correct option: C
4
Option C (4) is correct because the equation sin⁡2θ−2sin⁡θ−1=0\sin^2 \theta - 2 \sin \theta - 1 = 0 has exactly 4 distinct values of θ\theta in the interval [0,nπ][0, n\pi] when n = 4.

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