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JEE MATHEMATICS MCQ: RATE MEASURE

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Application +4 | -1

The speed

v

of a particle moving along a straight line is given by

a+b v^2=x^2

where

x

is its distance from the origin. The acceleration of the particle is

View answer and explanation

Correct option: A

\frac{x}{b}

Option B (

10 \sqrt{3} \mathrm{~cm}^2 / \mathrm{sec}

) is correct because it is the rate of increase of the area when each side is 10 cm.

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The surface area of a sphere when its volume is increasing at the same rate as its radius, is A particle is moving in a straight line has velocity and displacement equation as

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m

. The initial velocity of the particle is The diagonal of a square is changing at the rate of 0.5 cm

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. Then, the rate of change of area , when the area is 400

c{m^2}

is equal to A spherical balloon is filled with

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cubic meters of helium gas. If a leak in the balloon causes the gas to escape at the rate of

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\frac{1}{2 \pi+16}

\mathrm{cm} / \mathrm{sec}

, then the rate of change of volume of the box when radius is

2 \mathrm{~cm}

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