If half life of radium is ${\rm{77 }}\,{\rm{days}}$. Its decay constant in day will be

$9\,\, \times \,\,{10^{ - 3}}/{\rm{day}}$

$3 \times \,\,\,\,{10^{ - 13}}/{\rm{day}}$

$1\,\, \times \,\,{10^{ - 3}}/{\rm{day}}$

$6\,\, \times \,\,{10^{ - 3}}/{\rm{day}}$

NEET UG PHYSICS MCQ: NUCLEI

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Application +4 | -1

If half life of radium is

\mathrm{77 }\,\mathrm{days}

. Its decay constant in day will be

View answer and explanation

Correct option: B

9\,\, \times \,\,{10^{ - 3}}/\mathrm{day}

Option B (

9\, \times \,{10^{ - 3}}/\mathrm{day}

) is correct because the decay constant is calculated using the half-life formula.

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