JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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Application +4 | -1

A solid sphere is rotating about a diameter at an angular velocity

\omega

. If it cools so that its radius reduces to

\frac{1}{n}

of its original value, its angular velocity becomes

View answer and explanation

Correct option: D

{n^2}\omega

Option D (

{n^2}\omega

) is correct because angular momentum is conserved, and the moment of inertia changes with the square of the radius.

More Questions from SYSTEM OF PARTICLES

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\mathrm{AB}

\mathrm{L}

\mu(x)=a+\frac{b x}{L}

x

\mathrm{A}

\mathrm{CM}

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

1.0 \mathrm{~g}

8 \mathrm{~cm}

\omega = {t^4} + 2{t^3}

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)