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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Given that f(a+b+1−x)=f(x)f(a+b+1-x)=f(x) for all x∈Rx \in R. The value 1a+b∫abx{f(x)+f(x+1)}dx\frac{1}{a+b} \int_a^b x\{f(x)+f(x+1)\} d x is equal to
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Correct option: D
∫a−1b−1f(x+1)dx\int_{a-1}^{b-1} f(x+1) d x
The correct answer is C (∫a−1b−1f(x+1)dx\int_{a-1}^{b-1} f(x+1) d x) because using the given property and substitution, the integral can be simplified to this form.

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