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JEE MATHEMATICS MCQ: PERMUTATIONS

1 Easy

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Analyzing +4 | -1

The ten’s digit in

1! + 4! + 7! + 10! + 12! + 13! + 15! + 16! + 17!

is divisible by

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Correct option: B

3!

Option B (3!) is correct because the ten's digit of the sum is 6, which is divisible by 3! (6).

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