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JEE MATHEMATICS MCQ: LIMITS

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lim⁡x→0(π4x−π2x(eπx+1))\lim \limits_{{x \rightarrow 0}}\left(\frac{\pi}{4 x}-\frac{\pi}{2 x\left(e^{\pi x}+1\right)}\right) equals
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Correct option: D
π28\frac{\pi^2}{8}
Option D (π28\frac{\pi^2}{8}) is correct because after simplifying the expression and applying L'Hôpital's rule, the limit evaluates to π28\frac{\pi^2}{8}.

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