Skip to main content
Back to WAVE OPTICS

JEE PHYSICS MCQ: WAVE OPTICS

1 Medium
1 of 1
Application +4 | -1
In Young’s double slit experiment, distance between two slits is 0.28  mm0.28\;\mathrm{mm} and distance between slits and screen is 1.4  m1.4\;\mathrm{m}. Distance between central bright fringe and third bright fringe is 0.9  cm0.9\;\mathrm{cm}, what is the wavelength of light used?
View answer and explanation
Correct option: B
6000A∘6000\mathop \mathrm{A}\limits^ \circ
Option B (6000A∘6000\mathop \mathrm{A}\limits^ \circ) is correct because the wavelength is calculated using the formula for fringe width in Young's double-slit experiment.

More Questions from WAVE OPTICS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.