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NEET UG PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

1 Medium

1 of 1

Application +4 | -1

The work done in increasing the size of a rectangular soap film with dimensions

8\mathrm{cm} \times 3.75

cm to

10\mathrm{cm} \times 6\mathrm{cm}

is

2 \times {10^{ - 4}}

J. The surface tension of the film in

N{m^{- 1}}

is

View answer and explanation

Correct option: B

3.3 \times {10^{ - 2}}

Option B (

3.3 \times {10^{ - 2}}

) is correct because it is the surface tension calculated from the work done and the change in area of the soap film.

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Reason R: A change in the pressure applied to an enclosed incompressible fluid is transmitted undiminished to every portion of the fluid and to the walls of its container.

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