JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

The sum to infinity of the

G P

\frac{-5}{4}, \frac{5}{16}, \frac{-5}{64}, \ldots

, is

View answer and explanation

Correct option: C

-1

Option C (-1) is correct because the sum to infinity of the given GP is calculated using the formula S = a/(1-r) where a = -5/4 and r = -1/4.

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

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\log \left(\frac{a}{3 b}\right)

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a, b, c

\frac{3}{4}