JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

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Analyzing +4 | -1

x>1, y>1, z>1

are in G.P., then

\frac{1}{1+\ln x}, \frac{1}{1+\ln y}, \frac{1}{1+\ln z}

are in

View answer and explanation

Correct option: B

Option B (HP) is correct because if x, y, z are in GP, then ln(x), ln(y), ln(z) are in AP, and 1/(1+ln(x)), 1/(1+ln(y)), 1/(1+ln(z)) are in HP.

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

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y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

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a, b, c

\frac{3}{4}