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JEE MATHEMATICS MCQ: HYPERBOLIC FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

The imaginary part of

\cosh (\alpha+1 \beta)

is:

View answer and explanation

Correct option: B

\sinh \alpha \sin \beta

Option B (

\sinh \alpha \sin \beta

) is correct because it is the imaginary part of the expansion of

\cosh (\alpha+i \beta)

using hyperbolic trigonometric identities.

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\cos (x+h y)

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{H}: {xy}-{y}-2 {x}-2=0

. If normal drawn to

{H}

{P}(3,4)

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Q(\alpha+1, \beta+1)

\frac{\alpha}{\beta}

is The imaginary part of

\log \sin (x+i y)

{\sinh ^{ - 1}}\,\,2 + {\sinh ^{ - 1}}\,\,3 = x\; \Rightarrow \cosh \,\,x

\frac{{1 + \mathrm{tanh\;}\,\,\frac{x}{2}}}{{1 - \mathrm{tanh\;}\,\,\frac{x}{2}}}

is equal to Which of the following functions is not defined at

x=0