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JEE CHEMISTRY MCQ: ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

1 Medium
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Analyzing +4 | -1
But-2-yne is reacted separately with one mole of Hydrogen as shown below
B‾←liq NH3NaCH3−C+H2≡C−CH3→ΔPd/CA‾\underline B \xleftarrow[{{\text{liq }}N{H_3}}]{{Na}}C{H_3} - \mathop C\limits_{ + {H_2}} \equiv C - C{H_3}\xrightarrow[\Delta ]{{Pd/C}}\underline A
(A) A is more than soluble than B.
(B) The boiling point & melting point of A are higher and lower than B respectively.
(C) A is more polar than B because dipole moment of A is zero.
(D) Br2Br_2 adds easily to B than A.
Identify the incorrect statements from the option given below
View answer and explanation
Correct option: B
B, C & D only
The correct answer is B (B, C & D only) because the boiling point of A (cis-But-2-ene) is higher than B (trans-But-2-ene), A is more polar than B, and Br2Br_2 adds more easily to A than B.

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