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NEET UG PHYSICS MCQ: ATOMS

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Application +4 | -1
Taking the wavelength of first Balmer line in the hydrogen spectrum (n=3(n=3 ton =2)=2) as 660 nm660 \mathrm{~nm}, then the wavelength of 2nd 2^{\text {nd }} balmer line in the same spectrum (n=4(n=4 ton =2)=2) will be
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Correct option: A
488.9 nm488.9 \mathrm{~nm}
Option A (488.9 nm488.9 \mathrm{~nm}) is correct because it is calculated using the Rydberg formula for the Balmer series, considering the transition from n=4 to n=2.

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