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JEE PHYSICS MCQ: WAVES

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A standing wave is maintained in a homogeneous string of cross-sectional area ss and density ρ\rho. It is formed by the superposition of two waves travelling in opposite directions given by the equation y1=asin⁡(ωt−kx)y_1=a \sin (\omega t-k x) and y2=2asin⁡(ωt+kx)y_2=2 a \sin (\omega t+k x). The total mechanical energy confined between the sections corresponding to the adjacent antinodes is
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Correct option: C
5πspω2a22k\frac{5 \pi s p \omega^2 a^2}{2 k}
The correct answer is C. The total mechanical energy is calculated by summing the energy densities of the two waves and multiplying by the volume between adjacent antinodes.

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