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NEET UG CHEMISTRY MCQ: SOLID STATE

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Analyzing +4 | -1
A compound of formula A2B3{A_2}{B_3} has the hcp lattice. Which atom forms the hcp lattice and what fraction of tetrahedral voids is occupied by the other atoms?
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Correct option: C
hcp lattice-BB, 13\frac{1}{3} tetrahedral voids-AA
Option C (hcp lattice-BB, 13\frac{1}{3} tetrahedral voids-AA) is correct because in an hcp lattice, the number of atoms is 6, and the number of tetrahedral voids is 12. The formula A2B3A_2B_3 implies that B forms the hcp lattice, and A occupies 1/3 of the tetrahedral voids.

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