$({\text{I) C}}{{\text{H}}_3} - \mathop {\text{C}}\limits_{\begin{array}{*{20}{c}} | \\ {{\text{C}}{{\text{H}}_3}} \end{array}}^{\begin{array}{*{20}{c}} {{\text{C}}{{\text{H}}_3}} \\ | \end{array}} - {\text{OH}}$ $({\text{II) C}}{{\text{H}}_3} - \mathop {\text{C}}\limits_{\begin{array}{*{20}{c}} | \\ {\text{H}} \end{array}}^{\begin{array}{*{20}{c}} {{\text{C}}{{\text{H}}_3}} \\ | \end{array}} - {\text{OH}}$ (III) $\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2 \mathrm{OH}$ The correct order of rate of dehydration is:

JEE CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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({\text{I) C}}{{\text{H}}_3} - \mathop {\text{C}}\limits_{\begin{array}{cccccccccccccccccccc} | \\ {{\text{C}}{{\text{H}}_3}} \end{array}}^{\begin{array}{cccccccccccccccccccc} {{\text{C}}{{\text{H}}_3}} \\ | \end{array}} - {\text{OH}}

({\text{II) C}}{{\text{H}}_3} - \mathop {\text{C}}\limits_{\begin{array}{cccccccccccccccccccc} | \\ {\text{H}} \end{array}}^{\begin{array}{cccccccccccccccccccc} {{\text{C}}{{\text{H}}_3}} \\ | \end{array}} - {\text{OH}}

(III)

\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2 \mathrm{OH}

The correct order of rate of dehydration is:

View answer and explanation

Correct option: A

(I)

>

(II)

>

(III)

Option A ((I)

>

(II)

>

(III)) is correct because the rate of dehydration depends on the stability of the carbocation formed, and tertiary carbocations are more stable than secondary, which are more stable than primary.

JEE CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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