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NEET UG CHEMISTRY MCQ: SOLID STATE

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Analyzing +4 | -1
In a fcc lattice A,B,CA, B, C and DD atoms are arranged at corners, face centres octahedral voids and half of tetrahedral voids respectively and if the crystal deposited is defected such that all the particles at one body diagonal of each unit cell are missing, correspondingly then what is the resulted formula of the compound?
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Correct option: B
AB4C4D4{AB}_4 {C}_4 {D}_4
Option B (AB4C4D4{AB}_4 {C}_4 {D}_4) is correct because it accurately reflects the atom ratios after accounting for the missing atoms along the body diagonal.

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