NEET UG PHYSICS MCQ: MOTION IN A STRAIGHT LINE

1 Medium

1 of 1

Application +4 | -1

Position of particle during motion is expressed as

\vec r = \left( {5{t^2}\hat i + 3t\,\hat j} \right)m

. The magnitude of acceleration of particle at t = 0, is

View answer and explanation

Correct option: A

10\,m/{s^2}

Option A (

10\,m/{s^2}

) is correct because it is the magnitude of the acceleration vector calculated by finding the second derivative of the position vector with respect to time.

More Questions from MOTION IN A STRAIGHT LINE

Practice All Chapter MCQs →

Velocity-time curve for a body projected vertically upwards is Two cars A and B approach each other at the same speed, then what will be the velocity of A if velocity of B is

8 \mathrm{~m} / \mathrm{s}

? Two cars are moving in the same direction with a speed of

30\mathrm{km}{\mathrm{h}^{ - 1}}

. They are separated from each other by 5 km. Third car moving in the opposite direction meets the two cars after an interval of 4 min. What is the speed of the third car? A body is projected vertically up with ‘u’. Its velocity at half its maximum height is A scooter starts from rest have an acceleration of

1 \mathrm{~ms}^{-2}

while a car

150 \mathrm{~m}

behind it starts from rest with an acceleration of

2 \mathrm{~ms}^{-2}

. After how much time, the car catches up with the scooter? A motor vehicle travelled the first one third of a distance ‘S ’ at a speed of

{V_1} = 10\,kmph

, the second one third at a speed of

{V_2} = 20\,kmph

and the last one third at a speed of

{V_3} = 60\,kmph

determine the mean speed of the vehicle over the entire distance ‘S ’