JEE CHEMISTRY MCQ: HYDROCARBONS

1 Medium

1 of 1

Analyzing +4 | -1

Statement I : Bromination of neo-pentane forms optical isomers
Statement II : Neo-pentane has one

{4^ \circ }

carbon

View answer and explanation

Correct option: B

Only Statement II is true

Option B is correct because Statement II is true (neo-pentane has one quaternary carbon), but Statement I is false (bromination of neo-pentane does not form optical isomers).

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\mathrm{Ca}{\mathrm{C}_2} + {\mathrm{H}_2}\mathrm{O} \to X\xrightarrow{{{\mathrm{O}_3}/\frac{{{\mathrm{H}_2}\mathrm{O}}}{{\mathrm{O}{\mathrm{H}^ + }}}}}\mathrm{HCOOH} + \mathrm{HCOOH},X\;\mathrm{is}

In benzene, there is a delocalisation of π-electrons. Hence, each π-electron is attached by….carbon nuclei. Which statement is false? Assertion (A) In comparison to ethyl chloride, it is not easy to carry outnucleophilic substitution on vinyl chloride.

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\sigma

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