${\rm{C}}{{\rm{H}}_2} = {\rm{C}}{{\rm{H}}_2}$ reacts with ${\rm{HCI}}$ to form:

${\rm{C}}{{\rm{H}}_2}{\rm{ClC}}{{\rm{H}}_3}$

${\rm{C}}{{\rm{H}}_2}{\rm{C}}{{\rm{H}}_2}{\rm{C}}{{\rm{l}}_2}$

${\rm{C}}{{\rm{H}}_2}{\rm{ClC}}{{\rm{H}}_2}{\rm{Cl}}$

${\rm{C}}{{\rm{H}}_3}{\rm{CHC}}{{\rm{l}}_2}$

JEE CHEMISTRY MCQ: HYDROCARBONS

1 Easy

1 of 1

Application +4 | -1

\mathrm{C}{\mathrm{H}_2} = \mathrm{C}{\mathrm{H}_2}

reacts with

\mathrm{HCI}

to form:

View answer and explanation

Correct option: B

\mathrm{C}{\mathrm{H}_2}\mathrm{ClC}{\mathrm{H}_3}

The correct answer is

\mathrm{C}{\mathrm{H}_2}\mathrm{ClC}{\mathrm{H}_3}

because the reaction of

\mathrm{C}{\mathrm{H}_2} = \mathrm{C}{\mathrm{H}_2}

with

\mathrm{HCl}

results in an addition reaction forming

\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{Cl}