JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1

A physical quantity P is described by the relation

P = {a^{1/2}}{b^2}{c^3}{d^{ - 4}}

. If the relative errors in the measurement of a, b, c and d respectively are 2%, 1%, 3% and 5% then the relative error in P will be

View answer and explanation

Correct option: D

0.32

Option D (32%) is correct because it is the relative error in P calculated using the given relative errors in a, b, c, and d.

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