If $f\left( a \right) = 2,f'\left( a \right) = 1,g\left( a \right) = 3,g'\left( a \right) = - 1$, then $\mathop {\lim }\limits_{x \to a} \frac{{f\left( a \right)g\left( x \right) - f\left( x \right)g\left( a \right)}}{{x - a}}$ is equal to

JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Application +4 | -1

f\left( a \right) = 2,f'\left( a \right) = 1,g\left( a \right) = 3,g'\left( a \right) = - 1

, then

\lim\limits_{x \to a} \frac{{f\left( a \right)g\left( x \right) - f\left( x \right)g\left( a \right)}}{{x - a}}

is equal to

View answer and explanation

Correct option: D

- 5

Option D (-5) is correct because applying L'Hopital's rule and substituting the given values results in -5.