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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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The threshold energy is given as E0{E_0} and radiation of energy EE falls on metal, then K.E is given as
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Correct option: B
E−E0E - {E_0}
Option B (E−E0E - {E_0}) is correct because the kinetic energy (K.E) is the difference between the incident energy (E) and the threshold energy (E0{E_0}).

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