Skip to main content
Back to ELECTROMAGNETIC WAVES

JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

1 Medium
1 of 1
Application +4 | -1
The electric field of an electromagnetic wave is given by E=100sin⁡ω(t−xv)N/C.E=100 \sin \omega\left(t-\frac{x}{v}\right) N / C.

Find the energy contained in a hypothetical space of volume 100 cm3100 \mathrm{~cm}^3

(Given ϵ0=9×10−12C2N−1m−2)\left.\epsilon_0=9 \times 10^{-12} C^2 N^{-1} m^{-2}\right)
View answer and explanation
Correct option: C
2.25×10−12 J2.25 \times 10^{-12} \mathrm{~J}
Option C (2.25×10−12 J2.25 \times 10^{-12} \mathrm{~J}) is correct because the energy density of an electromagnetic wave is proportional to the square of the electric field, and the energy is the energy density times the volume.

More Questions from ELECTROMAGNETIC WAVES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.