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JEE PHYSICS MCQ: WAVE OPTICS

1 Medium
1 of 1
Application +4 | -1
nth{n^{th}} Bright fringe if red light (λ1=7500A∘)\left( {{\lambda _1} = 7500\mathop \mathrm{A}\limits^ \circ } \right) coincides with (n+1)th{\left( {n + 1} \right)^{th}} bright fringe of green light (λ2=6000A∘)\left( {{\lambda _2} = 6000\mathop \mathrm{A}\limits^ \circ } \right). The value of n=?n = ?
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Correct option: A
4
Option A (4) is correct because the condition for the coincidence of bright fringes is nλ1=(n+1)λ2n\lambda_1 = (n+1)\lambda_2, which can be solved for n.

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