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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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If 210=29⋅31+28⋅32+.....+2⋅39+310=S−211,{2^{10}} = {2^9} \cdot {3^1} + {2^8} \cdot {3^2} + ..... + 2 \cdot {3^9} + {3^{10}} = S - {2^{11}}, then SS is equal to
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Correct option: B
311{3^{11}}
The correct answer is B (3113^{11}) because it is the value of S, calculated by recognizing the given expression as a geometric progression and using the formula for the sum of a GP.

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