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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
Let 5f(x)+4f(1x)=1x+3,x>05 f(x)+4 f\left(\frac{1}{x}\right)=\frac{1}{x}+3, x > 0. Then 18∫12f(x)dx18 \int\limits_{{1}}^{2} f(x) d x is equal to
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Correct option: C
10log⁡e2−610 \log _{e} 2-6
Option C (10log⁡e2−610 \log _{e} 2-6) is correct because it is the value of the definite integral after solving the functional equation.

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