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JEE PHYSICS MCQ: CURRENT ELECTRICITY

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Application +4 | -1
A dry cell of emf 1.5  V\mathrm{1}\mathrm{.5 }\,\,\mathrm{V} and internal resistance 0.10  Ω\mathrm{0}\mathrm{.10}\,\,\mathrm{\Omega } is connected across a resistor in series with a very low resistance ammeter. When the circuit is switched on, the ammeter reading settles to a steady rate of 2 A\mathrm{2}\,\mathrm{A}. Find (i)\left( \mathrm{i} \right) chemical energy consumption of the cell (ii)\left( \mathrm{ii} \right) energy dissipation inside the cell (iii)\left( \mathrm{iii} \right) energy dissipation inside the resistor (iv)\left( \mathrm{iv} \right)power output of source is
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Correct option: A
(i)3W(ii)0.4W(iii)2.6W  (iv)2.6W\begin{array}{llllllllllllllllllll} {\left( \mathrm{i} \right)\mathrm{ 3 W }\left( {\mathrm{ii}} \right)\mathrm{ 0}\mathrm{.4 W }\left( {\mathrm{iii}} \right)\mathrm{ 2}\mathrm{.6 W\;}\left( {\mathrm{iv}} \right)\mathrm{ 2}\mathrm{.6 W}} \end{array}
Option A is correct. It correctly calculates the chemical energy consumption, energy dissipation inside the cell and resistor, and power output of the source.

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