JEE PHYSICS MCQ: MAGNETISM AND MATTER

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Application +4 | -1

The radius of the coil of a tangent galvanometer which has 10 turns is 0.1 m. The current required to produce a deflection of

60^\circ \;\left( {{B_H} = 4 \times {{10}^{ - 5}}\mathrm{\;T}} \right)

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Correct option: B

1.1 A

Option B (1.1 A) is correct because the current is calculated using the tangent galvanometer formula with the given magnetic field, radius, number of turns, and deflection angle.

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