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JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

Suppose that

g(x)=1+\sqrt{x}

and

f(g(x))=3+2 \sqrt{x}+x

, then

f(x)

is:

View answer and explanation

Correct option: B

2+x^2

The correct answer is B (

2+x^2

). By substituting

y = 1 + \sqrt{x}

into the given equation, we can find the expression for

f(x)

.

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

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f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

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f(x)=x^4

, Choose the correct answer. Which of the following functions are odd functions Let

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S=\left\{x: f(x)=f^{-1}(x)\right\}