The perimeter of triangle with vertices $(1, 0, 0), (0, 1, 0)$ and $(0, 0, 1)$ is $k \sqrt{2},$ where the value of $k$ is _______.

JEE MATHEMATICS MCQ: 3D GEOMETRY SYSTEM

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Application +4 | -1

The perimeter of triangle with vertices

(1, 0, 0), (0, 1, 0)

and

(0, 0, 1)

k \sqrt{2},

where the value of

k

is _______.

View answer and explanation

Correct option: A

3 \sqrt{2}

Option B (3) is correct because the perimeter is calculated by summing the lengths of the three sides, each of which is

\sqrt{2}

Practice All Chapter MCQs →

\left( { - 10,\;8} \right)

\left( { - 6,\;12} \right)

\left( {4,\; - 2} \right)

\left( { - 2,\;4} \right)

y z

(1,-2,4)

(3,-4

5)

p

2 x+y-3=0

3 x-y-2=0

x-p y+5=0

O\left( {0,0} \right),A\left( {a,0} \right)

B\left( {0,a} \right).

A(1,0,3)

B(4,7,1)

C(3,5,3)

\frac{x}{1}=\frac{y}{2}=\frac{z}{3}, \frac{x}{2}=\frac{y}{1}=\frac{z}{3}

\frac{x-1}{1}=\frac{2-y}{2}, z=3