NEET UG PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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Application +4 | -1

A ball is thrown vertically upwards from the top of a tower of height h with velocity v. The ball strikes the ground after

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Correct option: A

\frac{v}{\mathrm{g}}\left[ {1 + \sqrt {1 + \frac{{2\mathrm{g}h}}{{{v^2}}}} } \right]

Option A (

\frac{v}{\mathrm{g}}\left[ {1 + \sqrt {1 + \frac{{2\mathrm{g}h}}{{{v^2}}}} } \right]

) is correct because it is derived from the equations of motion, considering the initial upward velocity and the height of the tower.

More Questions from MOTION IN A STRAIGHT LINE

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8 \mathrm{~m} / \mathrm{s}

30\mathrm{km}{\mathrm{h}^{ - 1}}

1 \mathrm{~ms}^{-2}

150 \mathrm{~m}

2 \mathrm{~ms}^{-2}

{V_1} = 10\,kmph

{V_2} = 20\,kmph

{V_3} = 60\,kmph