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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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If (am)n=amn\left(a^{m}\right)^{n}=a^{m^{n}}, then the value of ' m′\mathrm{m}^{\prime} in terms of ' n\mathrm{n} ' is
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Correct option: C
n1/(n−1)n^{1 /(n-1)}
Option C (n1/(n−1)n^{1 /(n-1)}) is correct because solving the equation (am)n=amn(a^{m})^{n}=a^{m^{n}} for 'm' in terms of 'n' yields m=n1n−1m=n^{\frac{1}{n-1}}.

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