The area bounded by $\left| {x - 1} \right| \le 2\;{\rm{and}}\;{x^2} - {y^2} = 1$, is

$6\sqrt 2 + \frac{1}{2}\log |3 + 2\sqrt 2 |$

$6\sqrt 2 + \frac{1}{2}\log |3 - 2\sqrt 2 |$

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Medium

1 of 1

Analyzing +4 | -1

The area bounded by

\left| {x - 1} \right| \le 2\;\mathrm{and}\;{x^2} - {y^2} = 1

, is

View answer and explanation

Correct option: C

6\sqrt 2 - \log |3 + 2\sqrt 2 |

Option D (None of these) is incorrect; the correct answer is

6\sqrt 2 - \log |3 + 2\sqrt 2 |

which is obtained by evaluating the definite integral of the function within the given bounds.

Practice All Chapter MCQs →

\int \nolimits_0^\infty \,\,\log \,\,\left( {x + \frac{1}{x}} \right)\,\,\frac{{dx}}{{1 + {x^2}}}

f\left( x \right)

\int \nolimits_0^{{t^2}} \,\,x\;\,f\left( x \right)\,\,dx = \frac{2}{5}\,\,{t^5}

f\left( {\frac{4}{{25}}} \right)

\int\limits_{{0}}^{11}[x]^{3} . \mathrm{dx}

[*]

\int\limits_{2}^4 \frac{\log x^2}{\log x^2+\log \left(36-12 x+x^2\right)} d x

\int\limits_{{-2}}^0\left(x^3+3 x^2+3 x+3+(x+1) \cos (x+1)\right) d x

I\,\,\left( {m,\,\,n} \right) = \int \nolimits_0^1 \,\,{t^m}\,\,{\left( {1 + t} \right)^n}\,\,dt

I\left( {m,\,\,n} \right)

I\,\,\left( {m + 1,\,\,n + 1} \right)