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JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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Analyzing +4 | -1

In the reaction

\mathrm{Br}_2+\mathrm{Na}_2 \mathrm{CO}_3 \rightarrow \mathrm{NaBr}+\mathrm{NaBrO}_3+\mathrm{CO}_2

The equivalent weight of

\mathrm{NaBrO}_3

View answer and explanation

Correct option: C

\frac{\text {Molecular weight}}{5}

The correct answer is C (Molecular weight/5) because the equivalent weight of NaBrO3 is its molecular weight divided by the change in oxidation state of Br, which is 5.

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