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NEET UG PHYSICS MCQ: WAVE OPTICS

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Analyzing +4 | -1
Statement-1 : When light is incident from air to water then Brewster's angle is θB\theta_{{B}} then if light is incident from water to air then Brewster's angle is π2−θB\frac{\pi}{2}-\theta_{{B}}.
Statement-2 : When light goes from air to any medium of refractive index is then Brewster's angle (θB)\left(\theta_{{B}}\right) is given by θB=tan⁡−1(μ)\theta_{{B}}=\tan ^{-1}(\mu).
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Correct option: A
Both statement-1 and Statement-2 is true
Statement-1 and Statement-2 are both true. Brewster's angle relationship holds for both air to water and water to air incidence, and the formula for Brewster's angle is correctly stated.

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