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JEE PHYSICS MCQ: MAGNETISM AND MATTER

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Application +4 | -1
A bar magnet of magnetic moment 4.0 A−m24.0 \mathrm{~A}-\mathrm{m} 2 is free to rotate about a vertical axis through its center. The magnet is released from rest from east-west position. Kinetic energy of the magnet in north-south position will be (H=25μT)(\mathrm{H}=25 \mu \mathrm{T})
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Correct option: B
10−4 J10^{-4} \mathrm{~J}
Option B (10−4 J10^{-4} \mathrm{~J}) is correct because the kinetic energy gained is equal to the loss in potential energy as the magnet rotates from the east-west to the north-south position.

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