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NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

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Analyzing +4 | -1
A physical quantity T=abc2 d3e1/6\mathrm{T}=\frac{\sqrt{\mathrm{abc}^2}}{\mathrm{~d}^3 \mathrm{e}^{1 / 6}} is determined by measuring a, b, c, d, e separately with the percentage error of 1%,2%,3%,4%,3%1 \%, 2 \%, 3 \%, 4 \%, 3 \% respectively. Minimum amount of error is contributed by the measurement of :
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Correct option: C
a, e
Option C (a, e) is correct because the percentage errors of a and e contribute the least to the overall error in the calculated quantity T.

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