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JEE MATHEMATICS MCQ: ELLIPSE

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Application +4 | -1
The sum of the squares of the perpendicular on any tangent to the ellipse x2a2+y2b2=1\frac{x^2}{a^2}+\frac{y^2}{b^2}=1 from two points on the minor axis, each at a distance a2−b2\sqrt{a^2-b^2} from the centre, is
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Correct option: A
2a22 a^2
Option A (2a22 a^2) is correct because the sum of the squares of the perpendiculars simplifies to 2a22a^2 after algebraic manipulation and using the ellipse properties.

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