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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1
If α\alpha is a root of 25cos⁡2θ+5cos⁡θ−12=025 \cos ^2 \theta+5 \cos \theta-12=0, π2<α<π\frac{\pi}{2} < \alpha < \pi, then sin⁡2α\sin 2 \alpha is equal to
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Correct option: B
−2425-\frac{24}{25}
Option B (−2425-\frac{24}{25}) is correct because solving the quadratic equation for cos⁡α\cos \alpha and using the given range for α\alpha allows us to find sin⁡α\sin \alpha and then sin⁡2α\sin 2\alpha.

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