JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

x>0

and

\log _2 x+\log _2(\sqrt{x})+\log _2(\sqrt[4]{x})

+\log _2(\sqrt[8]{x})+\log _2(\sqrt[16]{x})+\ldots=4

, then

x

equals

View answer and explanation

Correct option: C

Option C (4) is correct because simplifying the logarithmic expression and solving for x gives x = 4.

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