JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

The number of divisors of

3 \times {7^3},\;7 \times {11^2}

and

2 \times 61

are in

View answer and explanation

Correct option: A

Option A (AP) is correct because the number of divisors of the given numbers forms an arithmetic progression with a common difference of -2.

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

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y=x-2

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\frac{3}{4}