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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
∫01  ({x}  [x+1])dx\int \nolimits_0^1 \,\,\left( {\left\{ x \right\}\,\,\left[ {x + 1} \right]} \right)dx (where { ⋅  }\left\{ {\, \cdot \,\,} \right\} denotes fractional part of xx and [ ⋅ ] \left[ {\, \cdot \,} \right]\, denotes greatest integer of x)x) is equal to
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Correct option: C
12\frac{1}{2}
Option C (12\frac{1}{2}) is correct because the integral simplifies to ∫01xdx\int_0^1 x dx due to the properties of fractional and greatest integer functions.

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