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JEE PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

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The dimensions of self inductance are
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Correct option: C
[ML2 T−2 A−2]\left[\mathrm{ML}^2 \mathrm{~T}^{-2} \mathrm{~A}^{-2}\right]
Option C (ML2 T−2 A−2\mathrm{ML}^2 \mathrm{~T}^{-2} \mathrm{~A}^{-2}) is correct because the dimensions of self-inductance can be derived from the energy stored in an inductor, U=(1/2)LI2U = (1/2)LI^2, where L is self-inductance and I is current.

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