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JEE PHYSICS MCQ: WAVE OPTICS

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In a Young's double slit experiment the angular width of a fringe formed on a distant screen is

1^{\circ}

. The wavelength of the light used is

6280\mathop {\text{A}}\limits^ \circ

. What is the distance between the two coherent sources?

View answer and explanation

Correct option: A

0.036 mm

Option B (0.063 mm) is the closest to the correct answer. The angular width is related to the wavelength and slit separation by

\alpha = \frac{\lambda}{d}

, so

d = \frac{\lambda}{\alpha}

.

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