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JEE PHYSICS MCQ: RAY OPTICS

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Application +4 | -1
If a thin prism of glass is dipped into water then minimum deviation (with respect to air) of light produced by prism will be left (aμg=32  and  aμw=43)\left( {_a{\mu _g} = \frac{3}{2}\,\,\mathrm{and}\,{\,_a}{\mu _w} = \frac{4}{3}} \right)
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Correct option: B
1 / 4\mathrm{1}\,\mathrm{/}\,\mathrm{4}
Option B (1 / 4\mathrm{1}\,\mathrm{/}\,\mathrm{4}) is correct because the minimum deviation changes when the prism is dipped in water, and the ratio of deviations is calculated using the refractive indices.

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